The three winningest contestants in the history of Jeopardy! will square off against each other on the game show in January, competing to see who will take home a whopping $1 million prize at the end of the tournament.
James Holzhauer, Ken Jennings, and Brad Rutter, who between them have won more than $10 million during their appearances on the show, will compete in a best-of-three face-off in which the winner of three matches will take home the top prize. Due to the structure of the game, the competition could go on for as many as seven days.
Jennings and Rutter have previously competed together, once against the supercomputer Watson and another time during an All-Star Match. Yet Holzhauer’s legendary streak, in which he won nearly $2.5 million and played the game like a “riverboat gambler,” according to one ABC executive, set the stage for a competition between the three most successful players the game has seen yet.
The show will air during prime time, a rarity for Jeopardy!, which traditionally broadcasts during the earlier evening hours.